document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364965>Question 364965</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the rectangle whose length is twice the width . the perimeter of the yard is 720 feet what are the dimensions of yer yard<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260182 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the rectangle whose length is twice the width . the perimeter of the yard is 720 feet what are the dimensions of yer yard\r<BR>\n" );
document.write( "\n" );
document.write( "Perimeter = 2L + 2W\r<BR>\n" );
document.write( "\n" );
document.write( "where L = length of rectangle in feet<BR>\n" );
document.write( "      W = width of rectangle in feet\r<BR>\n" );
document.write( "\n" );
document.write( "      L = 2W\r<BR>\n" );
document.write( "\n" );
document.write( "Perimeter = 2L + 2W<BR>\n" );
document.write( "      720 = 2L + 2W\r<BR>\n" );
document.write( "\n" );
document.write( "Since L = 2W, we get\r<BR>\n" );
document.write( "\n" );
document.write( "      720 = 2(2W) + 2W<BR>\n" );
document.write( "       6W = 720<BR>\n" );
document.write( "        W = 120\r<BR>\n" );
document.write( "\n" );
document.write( "        L = 2W = 2(120) = 240\r<BR>\n" );
document.write( "\n" );
document.write( "The dimensions of the yard are 120 feet and 240 feet </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );