document.write( "Question 364925: Find the vertex and intercepts of the parabola.\r
\n" ); document.write( "\n" ); document.write( "y = -3x^2 + 6x
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Algebra.Com's Answer #260173 by amoresroy(361)\"\" \"About 
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Vertex form of a parabola: y = a(x - h)^2 + k\r
\n" ); document.write( "\n" ); document.write( "Convert y = -3x^2 + 6x to vertex form of a parabola.\r
\n" ); document.write( "\n" ); document.write( "y = -3 (x^2 - 2x)\r
\n" ); document.write( "\n" ); document.write( "Completing the square\r
\n" ); document.write( "\n" ); document.write( "y = -3 (x^2 -2x + 1)- 1 + 3 \r
\n" ); document.write( "\n" ); document.write( "y = -3 (x - 1)^2 + 2\r
\n" ); document.write( "\n" ); document.write( "a = -3
\n" ); document.write( "h = 1
\n" ); document.write( "k = 2
\n" ); document.write( "-------------------
\n" ); document.write( "Vertex: (1,2)
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\n" ); document.write( "x-int.: y = 0 => 0 = -3x^2 + 6x
\n" ); document.write( "3x^2 = 6x
\n" ); document.write( "3x = 6
\n" ); document.write( "x = 2
\n" ); document.write( "--------------------------------
\n" ); document.write( "y-int.: x = 0 => y = y = -3(0)^2 + 6(0)
\n" ); document.write( "y = 0\r
\n" ); document.write( "\n" ); document.write( "The vertex is at (1,2). The x-intercept is 2 while the y-intercept is 0.
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