document.write( "Question 364925: Find the vertex and intercepts of the parabola.\r
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document.write( "y = -3x^2 + 6x \n" );
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Algebra.Com's Answer #260173 by amoresroy(361)![]() ![]() You can put this solution on YOUR website! Vertex form of a parabola: y = a(x - h)^2 + k\r \n" ); document.write( "\n" ); document.write( "Convert y = -3x^2 + 6x to vertex form of a parabola.\r \n" ); document.write( "\n" ); document.write( "y = -3 (x^2 - 2x)\r \n" ); document.write( "\n" ); document.write( "Completing the square\r \n" ); document.write( "\n" ); document.write( "y = -3 (x^2 -2x + 1)- 1 + 3 \r \n" ); document.write( "\n" ); document.write( "y = -3 (x - 1)^2 + 2\r \n" ); document.write( "\n" ); document.write( "a = -3 \n" ); document.write( "h = 1 \n" ); document.write( "k = 2 \n" ); document.write( "------------------- \n" ); document.write( "Vertex: (1,2) \n" ); document.write( "-------------------- \n" ); document.write( "x-int.: y = 0 => 0 = -3x^2 + 6x \n" ); document.write( "3x^2 = 6x \n" ); document.write( "3x = 6 \n" ); document.write( "x = 2 \n" ); document.write( "-------------------------------- \n" ); document.write( "y-int.: x = 0 => y = y = -3(0)^2 + 6(0) \n" ); document.write( "y = 0\r \n" ); document.write( "\n" ); document.write( "The vertex is at (1,2). The x-intercept is 2 while the y-intercept is 0. \n" ); document.write( " \n" ); document.write( " |