document.write( "Question 364944: you want to mix a 30% solution with a 80% solution to get 40 ounces of a 40% solution. how much of each solution do you need? \n" ); document.write( "
Algebra.Com's Answer #260162 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you have a 30% solution and you have an 80% solution. \n" ); document.write( "you want to get 40 ounces of a 40% solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 30% solution \n" ); document.write( "y = 80% solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".3x + .8y = .4 * 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first equation tells you the total ounces required for the solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "second equation tells you the total ounces required for the percent of the solution you are looking for.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve these 2 equations simultaneously and you have your answer.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your 2 equations are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 40 \n" ); document.write( ".3x + .8y = .4*40 = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by .3 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".3x + .3y = 12 \n" ); document.write( ".3x + .8y = 16\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the first equation from the second equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".5y = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of the resulting equation by .5 to getg:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since y = 8, then x must equal 32 because x + y = 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute 32 for x and 8 for y in the second equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".3x + .8y = 16 becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".3*32 + .8*8 = 16 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9.6 + 6.4 = 16 which becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16 = 16 which is true, confirming that the answer of x = 32 and y = 8 is good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In order to get a 40 ounces of a 40% solution, you require 32 ounces of a 30% solution and 8 ounces of an 80% solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "16 / 40 = 40% so you're good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "question was how much of each solution do you need?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "answer is 32 ounces of 30% solution and 8 ounces of 80% solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |