document.write( "Question 364904: Help:
\n" );
document.write( " Alberto left the store 2 hours before Cody. They drove in opposite direction. Cody drove at 20km/h for three hours. After this they were 435 km apart. find Alberto's speed.\r
\n" );
document.write( "\n" );
document.write( "Please help set up the problem for I know it has something too do with RT=D. just can't figure out the 3 hours. test is tomorrow. Much appreciated. \n" );
document.write( "
Algebra.Com's Answer #260139 by mananth(16946) You can put this solution on YOUR website! Alberto left the store 2 hours before Cody. They drove in opposite direction. Cody drove at 20km/h for three hours. After this they were 435 km apart. find Alberto's speed. \n" ); document.write( "... \n" ); document.write( "Cody 's speed = 20 mph \n" ); document.write( "cody time = 3hours \n" ); document.write( "D= rt \n" ); document.write( "Cody D= 3*20 = 60 miles. \n" ); document.write( ".. \n" ); document.write( "they were 435 miles away. \n" ); document.write( "435-60= 375 miles. \n" ); document.write( "... \n" ); document.write( "alberto drove 375 miles in 2+3 = 5 hours \n" ); document.write( "Alberto s=d/t \n" ); document.write( "s= 375/5 \n" ); document.write( "s= 75 mph. Alberto's speed. \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |