document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364851>Question 364851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is three less than twice another. The sum of their squares is 74. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #260113 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=260113\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One number is three less than twice another. The sum of their squares is 74. Find the numbers.<BR>\n" );
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document.write( "1st: x<BR>\n" );
document.write( "2nd: 2x-3<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x^2 + (2x-3)^2 = 74<BR>\n" );
document.write( "x^2 + 4x^2 -12x + 9 = 74<BR>\n" );
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document.write( "5x^2 -12x - 65 = 0<BR>\n" );
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document.write( "(x-5)(5x+13) = 0<BR>\n" );
document.write( "1st: x = 5<BR>\n" );
document.write( "2nd: 2x-3 = 7<BR>\n" );
document.write( "===============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );