document.write( "Question 364644: A machine that manufactures automobile parts is estimated to produce defective parts 6% of the time. If this estimate is correct, and 8 parts produced by this machine are randomly selected, what is the probability that at least 2 turn out to be defective? Round your answer to four decimal places. \r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #260023 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "Note: The probability of x successes in n trials is:
\n" ); document.write( ".
\n" ); document.write( "P = nCx* \"p%5Ex\"*\"q%5E%28n-x%29\" where p and q are the probabilities of success and failure respectively.
\n" ); document.write( "In this case p = .06 and q = .94
\n" ); document.write( "nCx = \"n%21%2F%28x%21%28n-x%21%29%29\"\r
\n" ); document.write( "\n" ); document.write( "P(at least 2 turn out to be defective)
\n" ); document.write( "1 - P(0 def) - P(1 defect)
\n" ); document.write( "P(0 def) = .94^8 = .610
\n" ); document.write( "P(1 defect) = 8C1*.06^1 .94^7 = 8*.06^1 .94^7 = 8*.06*.648 = .311
\n" ); document.write( "1 - .921 = .079 \n" ); document.write( "
\n" );