document.write( "Question 364612: Consider the curve y= 2/x with x>0. The normal to the curve y= 2x at point P untersects the y axis at (0,-3). Find the point P?
\n" ); document.write( "I understand the gradient of the normal is -2/x^2 and the equation using (0,-3)
\n" ); document.write( "making 2/x = -2/x^2-3 so -2/x^2-2/x-3 but can't think of where else to go\r
\n" ); document.write( "\n" ); document.write( "Note: At somepoint in the in solving this problem you may be required to solve a non trivial possibly high degree polynomial equation. in that case trial and error may be required but note that the answer should be a possitive integer smaller than 5 \n" ); document.write( "

Algebra.Com's Answer #260018 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
I'm confused by your question.
\n" ); document.write( "Consider $\"y=2%2Fx\"$ . OK
\n" ); document.write( "The normal to the curve $\"y=2x\"$ ?
\n" ); document.write( "Should this be normal to the curve $\"y=2%2Fx\"$ ? \n" ); document.write( "

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