document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364433>Question 364433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two alloys contain silver and copper in the ratios 3:1 and 5:3 respectively.The alloys are mixed to get a third alloy.Which of the following is the possible ratio of silver to copper in the third alloy ?<BR>\n" );
document.write( "1.5:2<BR>\n" );
document.write( "2.3:2<BR>\n" );
document.write( "3.4:1<BR>\n" );
document.write( "4.2:3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259997 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259997\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two alloys contain silver and copper in the ratios 3:1 and 5:3 respectively.<BR>\n" );
document.write( "The alloys are mixed to get a third alloy.<BR>\n" );
document.write( "Which of the following is the possible ratio of silver to copper in the third alloy ?<BR>\n" );
document.write( "1.5:2<BR>\n" );
document.write( "2.3:2<BR>\n" );
document.write( "3.4:1<BR>\n" );
document.write( "4.2:3<BR>\n" );
document.write( ":<BR>\n" );
document.write( "let a = 3:1 amt<BR>\n" );
document.write( "let b = 5:3 amt<BR>\n" );
document.write( "Write an equation assuming the 1st answer is possible,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F1 ALIGN=MIDDLE  ALT=\"3%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >a + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F2 ALIGN=MIDDLE  ALT=\"5%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(a + b)<BR>\n" );
document.write( "let a = 10 find b<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F1 ALIGN=MIDDLE  ALT=\"3%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >(10) + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F2 ALIGN=MIDDLE  ALT=\"5%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(b+10)<BR>\n" );
document.write( "30 + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F2 ALIGN=MIDDLE  ALT=\"5%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(b+10)<BR>\n" );
document.write( "multiply by 6 to clear the denominators,results:<BR>\n" );
document.write( "6(30) + 10b = 15(b+10)<BR>\n" );
document.write( "180 + 10b = 15b + 150<BR>\n" );
document.write( "180 - 150 = 15b - 10b<BR>\n" );
document.write( "30 = 5b<BR>\n" );
document.write( "b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30%2F5 ALIGN=MIDDLE  ALT=\"30%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "b = 6, so this is a possible answer<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Do the same with the 2nd answer<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F1 ALIGN=MIDDLE  ALT=\"3%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >a + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F2 ALIGN=MIDDLE  ALT=\"5%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(a + b)<BR>\n" );
document.write( "let a = 10 find b<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F1 ALIGN=MIDDLE  ALT=\"3%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >(10) + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F2 ALIGN=MIDDLE  ALT=\"3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(b+10)<BR>\n" );
document.write( "30 + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F2 ALIGN=MIDDLE  ALT=\"3%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >(b+10)<BR>\n" );
document.write( "multiply by 6 to clear the denominators,results:<BR>\n" );
document.write( "6(30) + 10b = 9(b+10)<BR>\n" );
document.write( "180 + 10b = 9b + 90<BR>\n" );
document.write( "10b - 9b = 90 - 180<BR>\n" );
document.write( "b = - 90, negative, 5:2 is not a possible answer<BR>\n" );
document.write( ":<BR>\n" );
document.write( "How about the 3rd answer; 4:1<BR>\n" );
document.write( "Do the same with the 2nd answer<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F1 ALIGN=MIDDLE  ALT=\"3%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >a + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = 4(a + b)<BR>\n" );
document.write( "let a = 10 find b<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3%2F1 ALIGN=MIDDLE  ALT=\"3%2F1\"   DISABLED_style= \"max-width:90%; height:auto;\" >(10) + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = 4(b+10)<BR>\n" );
document.write( "30 + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=5%2F3 ALIGN=MIDDLE  ALT=\"5%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" >b = 4(b+10)<BR>\n" );
document.write( "multiply by 3 to clear the denominators,results:<BR>\n" );
document.write( "3(30) + 5b = 12(b+10)<BR>\n" );
document.write( "90 + 5b = 12b + 120<BR>\n" );
document.write( "90 - 120 = 12b - 5b<BR>\n" );
document.write( "-30 = 7b; another neg, so 4:1 is not possible either<BR>\n" );
document.write( ":<BR>\n" );
document.write( "You can try the last answer the same way but 2:3 cannot be possible from the<BR>\n" );
document.write( "fact that 2 is less than 3. \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );