document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364549>Question 364549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object is projected vertically upward from the top of a building with an initial velocity of 112 ft/sec. Its distance in feet above the ground after t seconds is given by the equation \r<BR>\n" );
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document.write( "s (t) = -16t^2 + 112t + 87\r<BR>\n" );
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document.write( "Find its maximum distance above the ground </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259989 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259989\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> s(t) = -16t^2 + 112t + 87 <BR>\n" );
document.write( "by inspection (examination of coefficient associated with the t^2 term), we see that it is a parabola that opens downward (sad face).<BR>\n" );
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document.write( "The \"vertex\" will be give you the max height.<BR>\n" );
document.write( "Time at max height:<BR>\n" );
document.write( "t = -b/(2a) = -112/(2*(-16)) = -112/(-32) = 3.5 secs<BR>\n" );
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document.write( "To find height, plug it into the equation:<BR>\n" );
document.write( "s(t) = -16t^2 + 112t + 87 <BR>\n" );
document.write( "s(3.5) = -16(3.5)^2 + 112(3.5) + 87 <BR>\n" );
document.write( "s(3.5) = 283 feet<BR>\n" );
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