document.write( "Question 364574: Please help me factor this polynomial\r
\n" ); document.write( "\n" ); document.write( "6x^8+17x^4+12
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Algebra.Com's Answer #259988 by nerdybill(7384)\"\" \"About 
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6x^8+17x^4+12
\n" ); document.write( "If I
\n" ); document.write( "Let y = x^4
\n" ); document.write( "then
\n" ); document.write( "y^2 = x^8
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\n" ); document.write( "We can rewrite our original equation:
\n" ); document.write( "6x^8+17x^4+12
\n" ); document.write( "as
\n" ); document.write( "6y^2+17y+12 (which is more familiar)
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\n" ); document.write( "This can be factored as:
\n" ); document.write( "6y^2+17y+12
\n" ); document.write( "Rewrite the middle term:
\n" ); document.write( "6y^2+8y+9y+12
\n" ); document.write( "Group terms:
\n" ); document.write( "(6y^2+8y)+(9y+12)
\n" ); document.write( "Factor:
\n" ); document.write( "2y(3y+4) + 3(3y+4)
\n" ); document.write( "(3y+4)(2y+3)
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\n" ); document.write( "Put the above back into terms of x:
\n" ); document.write( "since y = x^4 we have:
\n" ); document.write( "(3x^4+4)(2x^4+3)\r
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