document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364563>Question 364563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this Applied Problem:\r<BR>\n" );
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document.write( "Every cross section of a drainage is an isosceles trapezoid with a small base of 3 feet and a height of 1 foot. Determine the width of the larger base that would give the ditch a cross-sectional area of 5ft^2.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259968 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Every cross section of a drainage is an isosceles trapezoid with a small base of 3 feet and a height of 1 foot. Determine the width of the larger base that would give the ditch a cross-sectional area of 5ft^2. <BR>\n" );
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document.write( "Area = (h/2)(b1+b2)<BR>\n" );
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document.write( "5 = (1/2)(3+b2)<BR>\n" );
document.write( "10 = 3+b2<BR>\n" );
document.write( "b2 = 7 ft<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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