document.write( "Question 364468: Mrs. Garson received 3 new students. There are a total of 210 different ways they could sit. How many seats are available for them to sit in? \n" ); document.write( "
Algebra.Com's Answer #259934 by sudhanshu_kmr(1152)\"\" \"About 
You can put this solution on YOUR website!
let the total no. of seat = x\r
\n" ); document.write( "\n" ); document.write( "then no. of ways by which 3 people can sit is xP3 = 210 ( x permutation 3)\r
\n" ); document.write( "\n" ); document.write( "=> x!/(x-3)! = 210\r
\n" ); document.write( "\n" ); document.write( "=>x*(x-1)*(x-2) = 210 \r
\n" ); document.write( "\n" ); document.write( "=> x* (x-1) *(x-2) = 2 * 3 * 5 *7 by factorizing 210\r
\n" ); document.write( "\n" ); document.write( " =>x*(x-1)*(x-2) = 7*6*5\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so, value of x is 7.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "no. of seats = 7\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );