document.write( "Question 364485: Alex has 95 cents in dimes and nickels. The total number of coins is 1 more than twice the number of dimes. How many coins of each type does Alex have?\r
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\n" ); document.write( "\n" ); document.write( "I know that one is Dx + Ny = 95 \n" ); document.write( "

Algebra.Com's Answer #259898 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Let x represent the number of dimes.  
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document.write( "question statets the total coins then is (2x + 1) 
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document.write( "The number of nickels is total coins - the number of dimes = [(2x+1) - x ]
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document.write( "Note: there are 5 cents in a nickel and 10 cents in a dime.
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document.write( "5[(2x+1) - x ] + 10x = 95 cents
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document.write( "simplify and slove for x
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document.write( "5[x + 1] + 10x = 95
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document.write( "5x + 5 + 10x = 95
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document.write( "15x = 90
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document.write( "x = 6, the number of dimes
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document.write( "number of nickles is [(2*6 + 1) - 6] = 7 nickels\r
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document.write( "checking our answer
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document.write( "5*7 + 6*10 = 35 cents + 60 cents = 95 cents \n" );
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