document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364482>Question 364482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,<BR>\n" );
document.write( "Im Struggeling with this question:\r<BR>\n" );
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document.write( "Vectors:\r<BR>\n" );
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document.write( "Show that vectors a = 2i-4j-k, b = 3i+2j-2k and c = 5i-2j-3k can form the sides of a triangle, find the length of each side and hence show that the triangle has a right angle. sketch the triangle of vectors, indicating their directions and the right angle,\r<BR>\n" );
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document.write( "Any help would be much appreciated?<BR>\n" );
document.write( "Thanks<BR>\n" );
document.write( "Scott </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259892 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Show that vectors a = 2i-4j-k, b = 3i+2j-2k and c = 5i-2j-3k can form the sides of a triangle, find the length of each side and hence show that the triangle has a right angle. sketch the triangle of vectors, indicating their directions and the right angle, <BR>\n" );
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document.write( "Find the lengths:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+sqrt%28i%5E2+%2B+j%5E2+%2B+k%5E2%29 ALIGN=MIDDLE  ALT=\"s+=+sqrt%28i%5E2+%2B+j%5E2+%2B+k%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+sqrt%284+%2B+16+%2B+1%29+=+sqrt%2821%29 ALIGN=MIDDLE  ALT=\"s+=+sqrt%284+%2B+16+%2B+1%29+=+sqrt%2821%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a: s = sqrt(21)<BR>\n" );
document.write( "b: s = sqrt(17)<BR>\n" );
document.write( "c: s = sqrt(38)<BR>\n" );
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document.write( "c^2 is = a^2 + b^2, so it's a right triangle.<BR>\n" );
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