document.write( "Question 364479: 1. If the random variable z is the standard normal score, is it true that P(-3 < z < 3) > 1? Why or why not?\r
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\n" ); document.write( "\n" ); document.write( "2. Givent a binomial distribution with n = 29 and p = 0.83, would the normal distribution provide a reasonable approximation? Why or why not?\r
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\n" ); document.write( "\n" ); document.write( "3. Find the area under the standard normal curve for the following: a). P(z < -0.25) b). P(0.55 < z < 0) c.) P(-1.91 < z < 1.06)
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Algebra.Com's Answer #259884 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1) \"P%28z%29=int%28p%28x%29%2Cdx%2C-infinity%2Cz%29\"
\n" ); document.write( "\"int%28p%28z%29%2Cdz%2C-infinity%2Cinfinity%29=1\"
\n" ); document.write( "So \"P\" can never be greater than \"1\".
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\n" ); document.write( "The binomial distribution is approximated by a normal distribution for any fixed \"p\"(even if \"p\" is small) as \"n\" is taken to infinity. \r
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\n" ); document.write( "3) \"P%28z%3C0.25%29=P%280.25%29\"
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\n" ); document.write( "\n" ); document.write( "\"+P%280.55+%3C+z+%3C+0%29=P%280.55%29-P%280%29\"
\n" ); document.write( "\"P%280.55+%3C+z+%3C+0%29=P%280.55%29-0.5\"
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\n" ); document.write( "\"+P%28-1.91+%3C+z+%3C+1.06%29=P%281.06%29-P%28-1.91%29\"
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