document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364463>Question 364463</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One angle of a triangle is three times as large as another. The measure of the third angle is 40 degrees more than that of the smallest angle. Find the measure of each angle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259867 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angle be x<BR>\n" );
document.write( "the second angle = 3x<BR>\n" );
document.write( "..<BR>\n" );
document.write( "the third angle = x+40<BR>\n" );
document.write( "...<BR>\n" );
document.write( "x+3x+x+40=180<BR>\n" );
document.write( "5x+40=180<BR>\n" );
document.write( "-40<BR>\n" );
document.write( "5x=180-40<BR>\n" );
document.write( "5x=140<BR>\n" );
document.write( "/5<BR>\n" );
document.write( "x=28 deg.<BR>\n" );
document.write( "...<BR>\n" );
document.write( "second angle = 3x=84 deg<BR>\n" );
document.write( "third angle = 40+28 = 68 deg.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "28+84+68=180<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );