document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364409>Question 364409</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve 3x^2 - 6x = 2 by completing the square? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259831 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x^2 - 6x = 2<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "x^2 - 2x = 2/3<BR>\n" );
document.write( "x^2-2x+1= 2/3 +1<BR>\n" );
document.write( "(x-1)^2=5/3<BR>\n" );
document.write( "take square root<BR>\n" );
document.write( "x-1=+/-sqrt(5/3)<BR>\n" );
document.write( "x= 1+sqrt(5/3)<BR>\n" );
document.write( "OR <BR>\n" );
document.write( "x=1-sqrt(5/3)<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );