document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364399>Question 364399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A foreman at a large plant estimates defective parts about 1% of the time. If the plant produces 30,000 parts in a week, what is the standard deviation (to the nearest tenth) for the number of defective parts? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259826 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This is a binomial experiment with n  = 30000, p = 0.01, and q = 1-p = 0.99.  The mean is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=mu+=+300 ALIGN=MIDDLE  ALT=\"mu+=+300\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the standard deviation is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sigma+=+sqrt%28npq%29+=+sqrt%2830000%2A0.01%2A0.99%29+=+17.2337 ALIGN=MIDDLE  ALT=\"sigma+=+sqrt%28npq%29+=+sqrt%2830000%2A0.01%2A0.99%29+=+17.2337\"   DISABLED_style= \"max-width:90%; height:auto;\" >, to 4 decimal places. </SPAN>\n" );
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