document.write( "Question 364347: the length of a rectangle is twice its width. the perimeter is 48in. Find the demension of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #259810 by Mr.positive(13)\"\" \"About 
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The length of a rectangle is twice its width.
\n" ); document.write( "The perimeter is 48 inches.
\n" ); document.write( "Find the dimensions of the rectangle.
\n" ); document.write( "The perimeter of a rectangle is the distance around the rectangle.
\n" ); document.write( "The rectangle has 2 short sides, which will be labeled with w, for width.
\n" ); document.write( "It also has 2 longer sides, which will be labeled with l, for the length.
\n" ); document.write( "The Perimeter around the object is therefore 2l + 2w
\n" ); document.write( "P= 2l + 2w.
\n" ); document.write( "If the width=x, then length= 2x.\r
\n" ); document.write( "\n" ); document.write( " Remember that the width= x inches \r
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\n" ); document.write( "P = 2l + 2w
\n" ); document.write( "48 = 2l +2w \r
\n" ); document.write( "\n" ); document.write( "length= 2x inches\r
\n" ); document.write( "\n" ); document.write( "P=2l + 2w
\n" ); document.write( "P= 2(2x) + 2(x)
\n" ); document.write( "48 = 4x + 2x; simplifying, you obtain
\n" ); document.write( "48 = 6x; solving for x, you obtain
\n" ); document.write( "8 = x
\n" ); document.write( "or, x = 8
\n" ); document.write( "w = x = 8 inches
\n" ); document.write( "l = 2x = 2(8 inches) = 16 inches.\r
\n" ); document.write( "\n" ); document.write( "mathteacher2010@aol.com \r
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