document.write( "Question 364295: the lenght of a rectangle is 6cm longer than the width.If the lenght of a rectangle is 6cm longer than the width.if the lenght is increased by 9cm and the width by 5 cm,the perimeter will be 160cm
\n" ); document.write( ".find the dimensions of the original retangle
\n" ); document.write( "

Algebra.Com's Answer #259754 by amoresroy(361)\"\" \"About 
You can put this solution on YOUR website!
Let L = length
\n" ); document.write( " W = width
\n" ); document.write( "Perimeter of a rectangle = 2L + 2W
\n" ); document.write( "-----------------------------------
\n" ); document.write( "L = w + 6
\n" ); document.write( "L + 9
\n" ); document.write( "W + 5
\n" ); document.write( "--------------------------
\n" ); document.write( "2L + 2W = 160
\n" ); document.write( "2(w + 6 + 9) + 2(w + 5) = 160
\n" ); document.write( "2w + 30 +2w +10 = 160
\n" ); document.write( "4w = 120
\n" ); document.write( "w = 30
\n" ); document.write( "--------------------------
\n" ); document.write( "L = w + 6
\n" ); document.write( "L = 30 + 6
\n" ); document.write( "L = 36
\n" ); document.write( "
\n" );