document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364269>Question 364269</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 10 inch T.v. set  has a width of 8 inches, so what is the height? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259731 by </B><A HREF=/tutors/aboutme.mpl?userid=npinson90><B>npinson90(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=npinson90><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259731\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would use the pythagorean theorem to solve this problem. <BR>\n" );
document.write( "Since televisions are measured diagonally, you have a right triangle. <BR>\n" );
document.write( "Our hypotenuse is 10 and we will consider the width {b=8}. <BR>\n" );
document.write( "Our unknown is a.\r<BR>\n" );
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document.write( "(a^2)+(b^2)=(c^2)<BR>\n" );
document.write( "So we have (a^2)+(8^2)=(10^2)\r<BR>\n" );
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document.write( "(a^2)+64=100\r<BR>\n" );
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document.write( "(a^2)+64-64=100-64\r<BR>\n" );
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document.write( "(a^2)=36\r<BR>\n" );
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document.write( "Now we will take the square root of 36, and it happens to <BR>\n" );
document.write( "be a perfect square so there are 2 solutions = (-6, 6) <BR>\n" );
document.write( "Since -6 is not a possible length, we will throw out that solution. \r<BR>\n" );
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document.write( "Answer, the height is 6 inches.\r<BR>\n" );
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