document.write( "Question 364182: The height of a falling object dropped form a height of 100m is described by h=100-16t2 where t is time measured in seconds. \r
\n" ); document.write( "\n" ); document.write( "Find i) The velocity at t = 2
\n" ); document.write( "ii) The acceleration at t = 2
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Algebra.Com's Answer #259722 by Earlsdon(6294)\"\" \"About 
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The height (as a function of time, t) of an object falling from 100 meters is described by:
\n" ); document.write( "\"h%28t%29+=+100-16t%5E2\"
\n" ); document.write( "i) Find the velocity at t = 2
\n" ); document.write( "The velocity is the rate of change of distance with respect to time, t.
\n" ); document.write( "If we take the first derivative of the height fuction, we will get the eqation for the velocity.
\n" ); document.write( "\"dh%2Fdt+=+-32t\" and at t=2, we get:
\n" ); document.write( "\"dh%2Fdt+=+-32%282%29\" \"dh%2Fdt+=+v\"
\n" ); document.write( "\"v+=+-64\"meters/second. The negative indicates a downward direction.
\n" ); document.write( "ii) Find the acceleration at t = 2.
\n" ); document.write( "Acceleration, which is the rate of change of velocity with respect to time, t, can be found by taking the second derivative of the height function (\"h%28t%29+=+100-16t%5E2\"):
\n" ); document.write( "\"d%5E2t%2Fdt%5E2+=+d%28dh%2Fdt%29%2Fdt\"=\"d%28-32t%29%2Fdt+=+-32\"meters/second squared.
\n" ); document.write( "\"d%5E2t%2Fdt%5E2+=+a\"
\n" ); document.write( "\"a+=+-32\"meters/second squared. A constant.
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