document.write( "Question 40557: Two resistors,when connected in series,have a total resistance of 40 ohms.When connected in parallel their total resistance is 8.4 ohms.If one of the resistors has a resistance of Rx ohms:
\n" ); document.write( "(a) show that Rx^2-40Rx+336=0
\n" ); document.write( "&
\n" ); document.write( "(b)calculate the resistance of each.
\n" ); document.write( "answers ( 12 ohms,28 ohms)
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Algebra.Com's Answer #25969 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"R%281%29+%2B+R%282%29+=+40\"
\n" ); document.write( "\"1%2FR%281%29+%2B+1%2FR%282%29+=+1%2F8.4\"
\n" ); document.write( "\"R%5E2+-40R+%2B+336+=+0\"
\n" ); document.write( "\"R+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"R+=+%2840+%2B-+sqrt%28+%28-40%29%5E2-4%2A1%2A336+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "\"R+=+%2840+%2B-+sqrt%28+1600+-+1344+%29%29%2F+2+\"
\n" ); document.write( "\"R+=+%2840+%2B-+sqrt%28+256+%29%29%2F+2+\"
\n" ); document.write( "\"R+=+20+%2B+8\"
\n" ); document.write( "\"R+=+20+-+8\"
\n" ); document.write( "R = 28,12
\n" ); document.write( "check these values
\n" ); document.write( "\"R%281%29+%2B+R%282%29+=+40\"
\n" ); document.write( "\"1%2FR%281%29+%2B+1%2FR%282%29+=+1%2F8.4\"
\n" ); document.write( "\"28+%2B+12+=+40\"
\n" ); document.write( "OK
\n" ); document.write( "\"1%2F28+%2B+1%2F12+=+1%2F8.4\"
\n" ); document.write( "multiply both sides by 4
\n" ); document.write( "\"1%2F7+%2B+1%2F3+=+1%2F2.1\"
\n" ); document.write( "multiply both sides by 21
\n" ); document.write( "\"3+%2B+7+=+10\"
\n" ); document.write( "OK
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