document.write( "Question 363981: Help! I don't know how to solve this!\r
\n" ); document.write( "\n" ); document.write( "one rectangle is (2x + 3) units wide and (7x - 5) units long. A second rectangle has a width of (3x - 9) units and a length of (8x - 2) units. Which has the greater area? How much greater?
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Algebra.Com's Answer #259662 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
Rectangle 1: (2x+3)(7x-5)=14x^2+11x-15
\n" ); document.write( "Rectangle 2: (3x-9)(8x-2)=24x^2-78x+18
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\n" ); document.write( "14x^2+11x-15=0
\n" ); document.write( "x=-1.5, x=.714... Between x=-1.5 and x=.714 y is negative.
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\n" ); document.write( "24x^2-78x+18=0
\n" ); document.write( "x=.25, x=3 Between x=.25 and x=3 y is negative.
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\n" ); document.write( "24x^2-78x+18-(14x^2+11x-15)=10x^2-89x+33
\n" ); document.write( "10x^2-89x+33=0
\n" ); document.write( "x=.3877..., x=8.512...
\n" ); document.write( "For \".25%3Cx%3C.714\" both rectangles have a negative area.
\n" ); document.write( "For \".714%3Cx%3C8.512\" Rectangle 1 has a larger area than rectangle 2
\n" ); document.write( "For \"0%3Cx%3C.25\" and \"8.512%3Cx%3Cinfinity\" rectangle 2 has a larger area than rectangle 1.
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