document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=364006>Question 364006</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Create the quadratic equation in the form y=ax^2+bx+c using the point (-5,6) as a point on the graph and (9,-9) as the vertex.<BR>\n" );
document.write( "I know the answers, I'm just not sure how to start solving for it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259615 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259615\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the vertex form : <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+a%28x-h%29%5E2+%2B+k ALIGN=MIDDLE  ALT=\"y+=+a%28x-h%29%5E2+%2B+k\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=a%28x-9%29%5E2-9 ALIGN=MIDDLE  ALT=\"y+=a%28x-9%29%5E2-9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Then plug in the respective coordinates of the given point (-5,6) into this equation to solve for a.  Think you can manage from there already. </SPAN>\n" );
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