document.write( "Question 363947: P(0.345≤z) \n" ); document.write( "
Algebra.Com's Answer #259581 by SadieKhan(31)![]() ![]() You can put this solution on YOUR website! Using a bit of technology \n" ); document.write( "Using mega sttat you get exactly upper and lower probability of a specified z value. \n" ); document.write( "For this question you get \n" ); document.write( " normal distribution \n" ); document.write( " p(lower) p(upper) z \n" ); document.write( " .6350 .3650 0.35\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "hence p(0.345<=z) = .3650 \n" ); document.write( " |