document.write( "Question 363931: Directions: \r
\n" ); document.write( "\n" ); document.write( "Use the compound interest formulas A=P(1+r/n )^nt and A=pe^rt to solve.
\n" ); document.write( "
\n" ); document.write( "Find the accumulated value of an investment of $850 at 4% compounded annually for 17 years.\r
\n" ); document.write( "\n" ); document.write( "Can someone show me what steps I need to use to find the answer? \r
\n" ); document.write( "\n" ); document.write( "Thanks!
\n" ); document.write( "

Algebra.Com's Answer #259574 by jrfrunner(365)\"\" \"About 
You can put this solution on YOUR website!
Both of these formulas are for computed compounded interest. \"A=P%281%2Br%2Fn+%29%5Ent+\" will approach the formula \"A=pe%5Ert\" in the limit as n approaches infintity. In other words limit as n-->infinity \"%281%2Br%2Fn+%29%5En+=e%5Er\"
\n" ); document.write( "--
\n" ); document.write( "n = number of periods to compound, P is the principal invested, r=annual rate and t=number of years.
\n" ); document.write( "--
\n" ); document.write( "In your case n=1 since you are compounding once a year and therefore you need to use the formula \"A=P%281%2Br%2Fn+%29%5Ent+\". The other formula would only be valid if you were compounding over very granular periods (ie days or hours) or n is very large.
\n" ); document.write( "--
\n" ); document.write( "given
\n" ); document.write( "n=1 compounded annually, p=850, r=4% or 0.04 and t=17
\n" ); document.write( "
\n" ); document.write( "\"A=P%281%2Br%2Fn+%29%5E%28nt%29+\"=\"850%2A%281%2B%28.04%2F1%29%29%5E%281%2A17%29=850%2A%281.04%29%5E17=1655.72+++\"
\n" ); document.write( "
\n" );