document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363900>Question 363900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle in a triangle is one and a half times the measure of the first. The third is 15 more than half the first angle. Find the measure of each angle in the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259541 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second angle in a triangle is one and a half times the measure of the first. The third is 15 more than half the first angle. Find the measure of each angle in the triangle<BR>\n" );
document.write( "---<BR>\n" );
document.write( "1st: x<BR>\n" );
document.write( "2nd: (3/2)x<BR>\n" );
document.write( "3rd:(x/2)+15<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x + (3/2)x + (x/2)+15 = 180<BR>\n" );
document.write( "3x + 15 = 180<BR>\n" );
document.write( "3x = 165<BR>\n" );
document.write( "x = 55 degrees<BR>\n" );
document.write( "---<BR>\n" );
document.write( "1st: x = 55 degrees<BR>\n" );
document.write( "2nd (3/2)x = 82.5 degrees<BR>\n" );
document.write( "3rd: (x/2)+15 = 42.5 degrees<BR>\n" );
document.write( "=================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "========= <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );