document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363876>Question 363876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find ordered pairs for 7y=4x+18 and y=-8x+54 please I cant seem to understand how to find solution by substitution???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259528 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259528\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "7y=4x+18 and y=-8x+54<BR>\n" );
document.write( "Here's how we do it. <BR>\n" );
document.write( "7(-8x+54)=4x+18 <BR>\n" );
document.write( "Rewritten as:<BR>\n" );
document.write( "-56x+378=4x+18<BR>\n" );
document.write( "Subtract 4x and 378 from both sides to get:<BR>\n" );
document.write( "-60x=-360<BR>\n" );
document.write( "Divide both sides by -60 to get:<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "Now we can find y by plugging 6 into either equation. <BR>\n" );
document.write( "y=6<BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );