document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363876>Question 363876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find ordered pairs for 7y=4x+18 and y=-8x+54 please I cant seem to understand how to find solution by substitution???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259527 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Equation 1:<BR>\n" );
document.write( " 7y=4x+18 \r<BR>\n" );
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document.write( "Equation 2:<BR>\n" );
document.write( " y=-8x+54 \r<BR>\n" );
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document.write( "Substitute the value of y in equation 2 to equation 1\r<BR>\n" );
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document.write( "Equation 1:<BR>\n" );
document.write( "7y=4x+18\r<BR>\n" );
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document.write( "7(-8x+54)      = 4x + 18<BR>\n" );
document.write( "7*(-8)x + 7*54 = 4x + 18\r<BR>\n" );
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document.write( "   -56x + 378  = 4x + 18<BR>\n" );
document.write( "     378 - 18  = 4x + 56x<BR>\n" );
document.write( "         360   = 60x<BR>\n" );
document.write( "           x   = 6\r<BR>\n" );
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document.write( "in equation 2<BR>\n" );
document.write( "y = -8x + 54\r<BR>\n" );
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document.write( "y = -8(6) + 54<BR>\n" );
document.write( "y = -48 +54<BR>\n" );
document.write( "y = 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );