document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363730>Question 363730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is more than twice its width, and the area of the rectangle is  . Find the dimensions of the rectangle.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259522 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The dimensions of the rectangle can be computed if area of rectangle is given.\r<BR>\n" );
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document.write( "Let x = width of rectangle<BR>\n" );
document.write( "   2x = length of rectangle\r<BR>\n" );
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document.write( "   A  = area of rectangle\r<BR>\n" );
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document.write( "   A  = x * 2x<BR>\n" );
document.write( "      = 2x ^2<BR>\n" );
document.write( "       <BR>\n" );
document.write( "2x^2  = A<BR>\n" );
document.write( " x^2  = A/2<BR>\n" );
document.write( "  x   = A^(1/2) / 2^(1/2)<BR>\n" );
document.write( " 2x   = 2A^(1/2) / 2^(1/2)<BR>\n" );
document.write( "   </SPAN>\n" );
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