document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363864>Question 363864</A>: <I><SPAN STYLE=\"word-break: break-all;\"> half the difference between two numbers is 2.the sum of the greater number and twice the smaller number is 13. find the numbers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259512 by </B><A HREF=/tutors/aboutme.mpl?userid=amoresroy><B>amoresroy(361)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amoresroy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=amoresroy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the smaller number<BR>\n" );
document.write( "    y = the greater number\r<BR>\n" );
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document.write( "(y - x)/2 = 2<BR>\n" );
document.write( "y - x     = 4     <BR>\n" );
document.write( "        y = 4 + x      (1) \r<BR>\n" );
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document.write( "y + 2x    = 13         (2)\r<BR>\n" );
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document.write( "Since y = 4 +x, eq. (2) becomes<BR>\n" );
document.write( "(4 + x) + 2x = 13<BR>\n" );
document.write( "          3x = 13-4<BR>\n" );
document.write( "           x = 3<BR>\n" );
document.write( "           y = 4 + 3<BR>\n" );
document.write( "           y = 7\r<BR>\n" );
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document.write( "The numbers are 3 & 7<BR>\n" );
document.write( " </SPAN>\n" );
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