document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=40534>Question 40534</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify\r<BR>\n" );
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document.write( "2sqrt12 + 4sqrt27.\r<BR>\n" );
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document.write( "I am coming up with an answer of 5sqrt3 - is this correct?<BR>\n" );
document.write( "I have the 2sqrt12 broken down to 2sqrt3 and 4sqrt27 broken down to3sqrt3.  That is where I got my answer from, by adding those. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25950 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25950\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2sqrt12+4sqrt27 or 2sqrt(4*3)+4sqrt(9*3) removing the sqrt numbers from the radical we get 2*2sqrt3+4*3sqrt3 or\r<BR>\n" );
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document.write( "4sqrt3+12sqrt3 or (4+12)sqrt3 or 16sqrt3 </SPAN>\n" );
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