document.write( "Question 363622: Please help me solve this equation:
\n" ); document.write( "Evaluate the following limits or explain why they do not exist.\r
\n" ); document.write( "\n" ); document.write( "a. \"+lim%28x-%3E0%2C+cotx%281-cosx%29+%29+\"
\n" ); document.write( "b. \"+lim+%28x-%3E0%2C+%28sinx%29%5Etanx+%29+\"
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Algebra.Com's Answer #259386 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
a. \"+lim%28x-%3E0%2C+cotx%281-cosx%29+%29++=+lim%28x-%3E0%2C+cosx%281-cosx%29%2Fsinx+%29\"
\n" ); document.write( "=\"lim%28x-%3E0%2C+cosx%29\"*\"lim%28x-%3E0%2C+%281-cosx%29%2Fsinx+%29\" = 1*0 = 0. The second limit was obtained by applying LHopital's rule.\r
\n" ); document.write( "\n" ); document.write( "b. Let \"y=+%28sinx%29%5Etanx\". then \"lny+=+tanx%2Alnsinx+=+lnsinx%2Fcotx\". The limit as x approaches 0 has the form \"infinity%2Finfinity\", so apply the LH rule. The new expression becomes \"%28cosx%2Fsinx%29%2F%28-csc%5E2x%29\". Simplifying this, we get \"cosx%2F%28-cscx%29+=+-sinxcosx\". As x goes to 0, -sinx*cosx approaches 0. Hence, lny approaches 0 as x approaches 0, and thus y approaches 1.
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