document.write( "Question 363691: A set of data is normally distributed with a mean of 200 and a standard deviation of 50. \r
\n" ); document.write( "\n" ); document.write( "What percentage of the scores is between 200 and 167?\r
\n" ); document.write( "\n" ); document.write( "What would be the percentile rank for a score of 176?\r
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Algebra.Com's Answer #259367 by stanbon(75887)\"\" \"About 
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A set of data is normally distributed with a mean of 200 and a standard deviation of 50.
\n" ); document.write( "What percentage of the scores is between 200 and 167?
\n" ); document.write( "z(200) = 0
\n" ); document.write( "z(167) = (167-200)/50 = -0.66
\n" ); document.write( "P(167< x < 200) = P(-0.66 < z < 0) = 0.2454
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\n" ); document.write( "What would be the percentile rank for a score of 176?
\n" ); document.write( "z(176) = (176-200)/50 = -0.48
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\n" ); document.write( "The percentile rank of a score is the proportion of
\n" ); document.write( "population below the score.
\n" ); document.write( "%ile of 176 = P(z< -0.48) = 0.3156 = 31.56%ile
\n" ); document.write( "Rounding the answer would be 32%ile
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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