document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=39596>Question 39596</A>: <I><SPAN STYLE=\"word-break: break-all;\"> looking desperately for the answer to this:\r<BR>\n" );
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document.write( "6x to the second power - 12x  -  18  =  ????\r<BR>\n" );
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document.write( "Please help... thank you, krista m pooler </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #25931 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=25931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6x^2 - 12x  -  18 = 0 \r<BR>\n" );
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document.write( "divide both sides by 6 and we get...........\r<BR>\n" );
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document.write( "x^2 - 2x  - 3 = 0 \r<BR>\n" );
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document.write( "splitting of middle term and we get......\r<BR>\n" );
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document.write( "x^2 - (3-1)x  - 3 = 0 \r<BR>\n" );
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document.write( "x^2 - 3x + 1x  - 3 = 0 \r<BR>\n" );
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document.write( "x(x-3) +1(x-3) = 0 \r<BR>\n" );
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document.write( "(x-3)(x+1)= 0 \r<BR>\n" );
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document.write( "either x = 3 or = -1\r<BR>\n" );
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document.write( "hope this will help u \r<BR>\n" );
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document.write( " </SPAN>\n" );
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