document.write( "Question 363589: how much pure acid should be mixed with 5 gallons of a 60% acid solution in order to get a 80% acid solution \n" ); document.write( "

Algebra.Com's Answer #259292 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi, 
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document.write( "Let x represent the amount of pure acid added (note: that is an 100% solution)
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document.write( ".60*5gal + 1.00*x = .80(5gal + x)
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document.write( "solve for x
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document.write( ".20x = .20*5gal
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document.write( "x = 5 gal of pure acid needs to be added.\r
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document.write( "checking our answer
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document.write( ".60*5gal + 5gal =  3gal + 5gal = .80*10gal = 8 gal \n" );
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