document.write( "Question 363595: my question is:\r
\n" ); document.write( "\n" ); document.write( "assume that x and y are positive numbers. Use the properties of logarithms to write the expression below in terms of the logarithms of x and y:\r
\n" ); document.write( "\n" ); document.write( "ln(x(y^7)) \r
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\n" ); document.write( "\n" ); document.write( "it is square root of y with a number 7 in the beginning dip of the square root. \r
\n" ); document.write( "\n" ); document.write( "I have tried:\r
\n" ); document.write( "\n" ); document.write( "lnx+lny^1/7
\n" ); document.write( "1/7(lnx+lny)\r
\n" ); document.write( "\n" ); document.write( "one other question:\r
\n" ); document.write( "\n" ); document.write( "Assume that x and y are positive numbers. Use the properties of logarithms to write the expression below as the logarithm of one quantity. 2 ln(x) +
\n" ); document.write( "1/2 ln(y)(and it is \"ln\" and not '#1\" by the n's.\r
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\n" ); document.write( "\n" ); document.write( "Ive tried lnx^2square root y
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Algebra.Com's Answer #259283 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi,
\n" ); document.write( "ln(x(y^7))
\n" ); document.write( "writing the expression in terms of the logarithms of x and y:
\n" ); document.write( "
\n" ); document.write( "ln(x(y^7)) = lnx + lny^7\r
\n" ); document.write( "\n" ); document.write( "2 ln(x) + 1/2 ln(y)
\n" ); document.write( "writing the expression as the logarithm of one quantity
\n" ); document.write( "
\n" ); document.write( "2 ln(x) + 1/2 ln(y) = ln(x^2) + ln(y^1/2)
\n" ); document.write( "
\n" ); document.write( "\"ln%28x%5E2%29+%2B+ln%28y%5E%281%2F2%29%29+=+ln%28x%5E2%2Ay%5E%281%2F2%29%29\"\r
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