document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363573>Question 363573</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.<BR>\n" );
document.write( "5^x = 32\r<BR>\n" );
document.write( "\n" );
document.write( "x= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259271 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259271\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 2^a = 5 and 2^b = 9. Using exponent rules, solve the equation in terms of a and/or b.<BR>\n" );
document.write( "5^x = 32\r<BR>\n" );
document.write( "\n" );
document.write( "if 2^a = 5, then log2 5 = a, log2 5 = (log10 5)/(log10 2) = a<BR>\n" );
document.write( "a = 2.3219 rounded to 4 places<BR>\n" );
document.write( "if 2^b = 9, then log2 9 = b, log2 9 = (log10 9)/(log10 2) = b<BR>\n" );
document.write( "b = 3.1699 rounded to 4 places<BR>\n" );
document.write( "if 5^x = 32, then log5 32 = x, log5 32 = (log10 32)/(log10 5) = x<BR>\n" );
document.write( "x = 2.1534 rounded to 4 places </SPAN>\n" );
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