document.write( "Question 363489: The diameter of apples in a certain orchard are normally distributed with a mean of 5.5 inches and a standard deviation of 0.65 inches. Show all work.\r
\n" ); document.write( "\n" ); document.write( "What percentage of the apple in this orchard have diameters less than 5.8 inches?\r
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\n" ); document.write( "\n" ); document.write( "What percentage of the apples in this orchard are larger than 6.3 inches?\r
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\n" ); document.write( "\n" ); document.write( "I can work the first part but I don't undersand how to get the second part. Can anyone show me what to do?\r
\n" ); document.write( "\n" ); document.write( "z(5.8) = (5.8 -5.55)/0.65 = 0.385
\n" ); document.write( "P(x < 5.8) = P(z < 0.385) = ?
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Algebra.Com's Answer #259249 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
First, your z value is off (you used 5.55 instead of 5.5).
\n" ); document.write( "\"z%5B1%5D=%28x-mu%29%2Fsigma=%285.8-5.5%29%2F0.65=0.462\"
\n" ); document.write( "\"P%28z%5B1%5D%29=0.678\"
\n" ); document.write( "67.8%
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\n" ); document.write( "\"z%5B2%5D=%286.3-5.5%29%2F0.65=1.231\"
\n" ); document.write( "\"P%28z%5B2%5D%29=0.891\"
\n" ); document.write( "89.1% of apples have diameter less than or equal to \"6.3\".
\n" ); document.write( "100%-89.1%=10.9% have diameters greater than \"6.3\".
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