document.write( "Question 363489: The diameter of apples in a certain orchard are normally distributed with a mean of 5.5 inches and a standard deviation of 0.65 inches. Show all work.\r
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document.write( "What percentage of the apple in this orchard have diameters less than 5.8 inches?\r
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document.write( "What percentage of the apples in this orchard are larger than 6.3 inches?\r
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document.write( "I can work the first part but I don't undersand how to get the second part. Can anyone show me what to do?\r
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document.write( "z(5.8) = (5.8 -5.55)/0.65 = 0.385
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document.write( "P(x < 5.8) = P(z < 0.385) = ? \n" );
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Algebra.Com's Answer #259249 by Fombitz(32388) You can put this solution on YOUR website! First, your z value is off (you used 5.55 instead of 5.5). \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "67.8% \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "89.1% of apples have diameter less than or equal to \n" ); document.write( "100%-89.1%=10.9% have diameters greater than \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |