document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363260>Question 363260</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diagram shows an isosceles right triangle.<BR>\n" );
document.write( "The two legs are \"x,\" and the hypotenuse is x radical 2.<BR>\n" );
document.write( "A. If its perimeter is 10, find x.<BR>\n" );
document.write( "B. If its area is 12, find x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259241 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The diagram shows an isosceles right triangle.<BR>\n" );
document.write( "The two legs are \"x,\" and the hypotenuse is x radical 2.<BR>\n" );
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document.write( "A. If its perimeter is 10, find x.<BR>\n" );
document.write( "x + x + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2Asqrt%282%29 ALIGN=MIDDLE  ALT=\"x%2Asqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 10<BR>\n" );
document.write( "2x + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2Asqrt%282%29 ALIGN=MIDDLE  ALT=\"x%2Asqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 10<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2Asqrt%282%29 ALIGN=MIDDLE  ALT=\"x%2Asqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = -2x + 10<BR>\n" );
document.write( "Square both sides<BR>\n" );
document.write( "x^2(2) = (-2x+10)^2<BR>\n" );
document.write( "FOIL (-2x+10)*(-2x+10)<BR>\n" );
document.write( "2x^2 = 4x^2 - 20x - 20x + 100<BR>\n" );
document.write( "2x^2 = 4x^2 - 40x + 100<BR>\n" );
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document.write( "Combine on the right<BR>\n" );
document.write( "0 = 4x^2 - 2x^2 - 40x + 100<BR>\n" );
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document.write( "A quadratic equation<BR>\n" );
document.write( "2x^2 - 40x + 100 = 0<BR>\n" );
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document.write( "Simplify, divide by 2<BR>\n" );
document.write( "x^2 - 20x + 50 = 0<BR>\n" );
document.write( "Use the quadratic formula to find x, a=1; b=-20; c=50<BR>\n" );
document.write( "Two solutions<BR>\n" );
document.write( "x = 17.06<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 2.93 is the only reasonable solution<BR>\n" );
document.write( "Check<BR>\n" );
document.write( "2(2.93) + <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.93%2Asqrt%282%29 ALIGN=MIDDLE  ALT=\"2.93%2Asqrt%282%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 10.00<BR>\n" );
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document.write( "B. If its area is 12, find x.<BR>\n" );
document.write( ".5(x*x) = 12<BR>\n" );
document.write( "multiply both sides by 2<BR>\n" );
document.write( "x^2 = 24<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2824%29 ALIGN=MIDDLE  ALT=\"sqrt%2824%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 4.9 <BR>\n" );
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document.write( "Check<BR>\n" );
document.write( ".5 * 4.9 * 4.9 = 12.0 </SPAN>\n" );
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