document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363510>Question 363510</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There are two right triangles back to back and the base of both triangles together is 20 and the two hypotenuses have a value of x.  I'm supposed to find the area of the triangles together. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259216 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259216\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let a=the common altitude of each triangle.<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "a^2+10^2=x^2 for one of the triangles.<BR>\n" );
document.write( "a^2=x^2-100<BR>\n" );
document.write( "a=sqrt(x^2-100)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "0.5ab=A(triangle)<BR>\n" );
document.write( "0.5*10(sqrt(x^2-100))<BR>\n" );
document.write( "=5*sqrt(x^2-100) area of one of the triangles.<BR>\n" );
document.write( "10*sqrt(x^2-100) area of the triangles together.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
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