document.write( "Question 363502: i need to figure out the answer what I can up with is wrong.
\n" ); document.write( "P =7t^2+7000 with a growth rate of 750 each year. For each of these years 2010,2011,2012,2013,2016
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Algebra.Com's Answer #259199 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
Your equation and your problem statement don't really track with each other.\r
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\n" ); document.write( "\n" ); document.write( "The equation is that of a quadratic equation that has an exponential growth rate each year.\r
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\n" ); document.write( "\n" ); document.write( "I will graph your equation to show you.\r
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\n" ); document.write( "\n" ); document.write( "In order to do that, I have to make y equal to P, and x equal to t.\r
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\n" ); document.write( "\n" ); document.write( "Your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "y = 7x^2 + 7000\r
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\n" ); document.write( "\n" ); document.write( "A graph of this equation would look like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-1%2C5%2C-1000%2C10000%2C7x%5E2+%2B+7000%29\"\r
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\n" ); document.write( "\n" ); document.write( "It looks like a flat line because the x value is increasing by 1 each time and the result is swallowed up by the 7000.\r
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\n" ); document.write( "\n" ); document.write( "Change the equation to y = 750x^2 + 7000 and you get:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-1%2C5%2C-1000%2C10000%2C750x%5E2+%2B+7000%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can see that the graph of the equation is now exponential.\r
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\n" ); document.write( "\n" ); document.write( "That's because you have x^2 rather than x.\r
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\n" ); document.write( "\n" ); document.write( "Change the equation to y = 750*x + 7000 and you get:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-1%2C5%2C-1000%2C10000%2C750%2Ax+%2B+7000%29\"\r
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\n" ); document.write( "\n" ); document.write( "That last equation is a straight line.\r
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\n" ); document.write( "\n" ); document.write( "In fact, it's a straight line with an annual increase of 750 per year.\r
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\n" ); document.write( "\n" ); document.write( "That's because this is a linear equation in the form of:\r
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\n" ); document.write( "\n" ); document.write( "y = mx + b, where:\r
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\n" ); document.write( "\n" ); document.write( "m is the slope, and b is the y-intercept.\r
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\n" ); document.write( "\n" ); document.write( "The slope is 750 which means that for every change in x, y will change by 750.\r
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\n" ); document.write( "\n" ); document.write( "The y-intercept is 7000 which means that when x = 0, y = 7000.\r
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\n" ); document.write( "\n" ); document.write( "To show you that this equation increases by 750 per year, you can simply plot the values of x.\r
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\n" ); document.write( "\n" ); document.write( "When x = 0, y = 750*0 + 7000 = 7000
\n" ); document.write( "When x = 1, y = 750*1 + 7000 = 7750
\n" ); document.write( "When x = 2, y = 750*2 + 7000 = 8500
\n" ); document.write( "When x = 3, y = 750*3 + 7000 = 9250
\n" ); document.write( "etc.\r
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\n" ); document.write( "\n" ); document.write( "I will plot 3 horizontal lines at 7750, 8500, 9250 to show you.\r
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\n" ); document.write( "\n" ); document.write( "Simply trace a vertical line down from the intersection of those horizontal lines with the graph of the equation and you will see that x = 0,1,2,3 respectively.\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-1%2C5%2C-1000%2C10000%2C750%2Ax+%2B+7000%2C7000%2C7750%2C8500%2C9250%29\"\r
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\n" ); document.write( "\n" ); document.write( "Unless I'm missing something, I don't think you have a valid equation to solve the problem given.\r
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\n" ); document.write( "\n" ); document.write( "If I'm all wet, then send me the original problem statement in its entirety and I'll look at it and give you my opinion.\r
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