document.write( "Question 40372: Whitney invested $11,000, part at 6% and part at 1%. If the total interest at the end of the year is $510, how much did she invest at 6%?\r
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Algebra.Com's Answer #25918 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! .06X+(11000-X).01=510 OR .06X+110-.01X=510 OR .05X=400 OR X=400/.05 OR X=$8000 INVESTED @ 6% AND 11000-8000=3000 INVESTED @ 1%\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |