document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363475>Question 363475</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The least and greatest numbers in a list of 7 real numbers are 2 and 20 ,respectively. The median of the list is 6 , and the number 3 occurs most often <BR>\n" );
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document.write( "which of the following could be the average (arithmetic mean) of the numbers in the list ?\r<BR>\n" );
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document.write( "I    7\r<BR>\n" );
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document.write( "II   8.5\r<BR>\n" );
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document.write( "III  10\r<BR>\n" );
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document.write( "(A)  I only\r<BR>\n" );
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document.write( "(B)I and II only\r<BR>\n" );
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document.write( "(c) I and III only \r<BR>\n" );
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document.write( "(D) II and III only \r<BR>\n" );
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document.write( "(E) I, II, and III<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259172 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (E) I, II, and III.<BR>\n" );
document.write( "We could have the following arrangement for the numbers:<BR>\n" );
document.write( "2,3,3,6,x,y,20, in ascending order.  The mean is formed as follows:<BR>\n" );
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document.write( "If the average is 7, then x+y = 15, which is very much possible for two numbers x and y between 6 and 20.(Take  7 and 8, e.g.) If the average is 8.5, then x+y = 25.5, which again is possible for two numbers between 6 and 20 (take 10 and 15.5, e.g.)  If the average is 10, then x+y = 36, which again is possible for two numbers between 6 and 20 (take 17 and 19, e.g.) \r<BR>\n" );
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