document.write( "Question 363456: one number is 7 more than a second number.Also,the sum of the square of the two numbers is 389.Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #259157 by mananth(16949)\"\" \"About 
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let the number be x & x+7
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\n" ); document.write( "x^2+(x+7)^2=389
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\n" ); document.write( "x^2+x^2+14x+49=389
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\n" ); document.write( "2x^2+14x+49-389=0
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\n" ); document.write( "2x^2+14x-340=0
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\n" ); document.write( "/2
\n" ); document.write( "x^2+7x-170=0
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\n" ); document.write( "x^2+17x-7x-170=0
\n" ); document.write( "x(x+17)-7(x+17)=0
\n" ); document.write( "(x+17)(x-7)=0
\n" ); document.write( "x=-17 OR x=7
\n" ); document.write( "...
\n" ); document.write( "The numbers are -17,-10\r
\n" ); document.write( "\n" ); document.write( "7,14 does not satisfy the equation
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\n" ); document.write( "m.ananth@hotmail.ca
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