document.write( "Question 363377: In a survey of adults throughout America 75% strongly support integration.You randomly select 24 adults ,throughout America and ask each if they strongly support integration.\r
\n" );
document.write( "\n" );
document.write( "a/ Show the the conditions for a binomial distribution are met\r
\n" );
document.write( "\n" );
document.write( "b/ Decide whether you can use the normal distribution to approximate the binomial distribution.\r
\n" );
document.write( "\n" );
document.write( "c/Find the Probability that 15 adults say they strongly support integration\r
\n" );
document.write( "\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #259147 by edjones(8007) You can put this solution on YOUR website! a. People either do or don't strongly support integration. \n" ); document.write( ". \n" ); document.write( "b. A normal distribution will not work here. this is a 75-25 proposition. \n" ); document.write( ". \n" ); document.write( "c. Let x=.75 and y=.25 \n" ); document.write( "24C15=1307504*x^15*y^9 \n" ); document.write( "=.0667 Probability that EXACTLY 15 adults say they strongly support integration. \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |