document.write( "Question 363419: Nan and Peg started on trips from New York City and traveled in opposite directions. Nan traveled 10 mph faster than Peg. If they were 450 miles apart after 5 hours, how fast was each person traveling? \n" ); document.write( "
Algebra.Com's Answer #259144 by mananth(16946)\"\" \"About 
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Nan and Peg started on trips from New York City and traveled in opposite directions. Nan traveled 10 mph faster than Peg. If they were 450 miles apart after 5 hours, how fast was each person traveling?
\n" ); document.write( "...
\n" ); document.write( "peg speed = xmph
\n" ); document.write( "Nan speed = x+10 mph
\n" ); document.write( "...
\n" ); document.write( "they travel in opposite directions
\n" ); document.write( "so speed is added up
\n" ); document.write( "x+x+10=2x+10
\n" ); document.write( "distance = 450 miles
\n" ); document.write( "..
\n" ); document.write( "time = 5 hours
\n" ); document.write( "...
\n" ); document.write( "450/(2x+10)=5
\n" ); document.write( "450=5(2x+10)
\n" ); document.write( "450=10x+50
\n" ); document.write( "add -50
\n" ); document.write( "450-50=10x+50-50
\n" ); document.write( "400=10x
\n" ); document.write( "x=400/10
\n" ); document.write( "x= 40 mph Peg's speed
\n" ); document.write( "Nan's speed = 40+10=50 mph
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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