document.write( "Question 363366: I need help on knowing how to solve linear systems in form of fractions. \r
\n" ); document.write( "\n" ); document.write( "the problem: (1/x+2) + (2/y+1) = 1
\n" ); document.write( " (4/x+2) + (9/y+1) = 13/3\r
\n" ); document.write( "\n" ); document.write( "i attempted the first equation\r
\n" ); document.write( "\n" ); document.write( "i multiplied the left side by (x+2) (y+1) and the right side as well. \r
\n" ); document.write( "\n" ); document.write( "so i got y+1+2x+4=xy+x+2y+2
\n" ); document.write( "then i subtracted x and y from both sides
\n" ); document.write( "5+x=xy+y+2
\n" ); document.write( "to get
\n" ); document.write( "xy+y-x-3=o \r
\n" ); document.write( "\n" ); document.write( "I do not know if this is correct, so i can't go on solving the problem because i don't know. Truthfully, im guessing at this point.
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Algebra.Com's Answer #259080 by amoresroy(361)\"\" \"About 
You can put this solution on YOUR website!
First Equation
\n" ); document.write( " Multiplying both sides of equation by (x+2) (y+1), gives you\r
\n" ); document.write( "\n" ); document.write( "1 (y+1) + 2 (x+2) = (x+2) (y+1)\r
\n" ); document.write( "\n" ); document.write( "y+1+2x+4 = xy + x + 2y + 2\r
\n" ); document.write( "\n" ); document.write( "xy - x +y = 3\r
\n" ); document.write( "\n" ); document.write( "So far your solution is correct. Proceed to simply the second equation.
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