document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=363366>Question 363366</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help on knowing how to solve linear systems in form of fractions. \r<BR>\n" );
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document.write( "the problem:  (1/x+2) + (2/y+1) = 1<BR>\n" );
document.write( "              (4/x+2) + (9/y+1) = 13/3\r<BR>\n" );
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document.write( "i attempted the first equation\r<BR>\n" );
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document.write( "i multiplied the left side by (x+2) (y+1) and the right side as well. \r<BR>\n" );
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document.write( "so i got y+1+2x+4=xy+x+2y+2<BR>\n" );
document.write( "then i subtracted x and y from both sides<BR>\n" );
document.write( "5+x=xy+y+2<BR>\n" );
document.write( "to get<BR>\n" );
document.write( "xy+y-x-3=o \r<BR>\n" );
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document.write( "I do not know if this is correct, so i can't go on solving the problem because i don't know. Truthfully, im guessing at this point. <BR>\n" );
document.write( "               </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #259074 by </B><A HREF=/tutors/aboutme.mpl?userid=user_dude2008><B>user_dude2008(1862)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=user_dude2008><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=259074\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (1/x+2) + (2/y+1) = 1 -----> y+1+2(x+2)=(x+2)(y+1)\r<BR>\n" );
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document.write( "(4/x+2) + (9/y+1) = 13/3  ----> 12(y+1)+27(x+2)=13(x+2)(y+1) </SPAN>\n" );
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